The slope of the line passing through (1, 2) and (3, 6) is:
Straight Lines — Important Questions
SUMMARY: The chapter on Straight Lines in Class 11 Mathematics explores the concepts and equations related to lines in a two-dimensional plane.
KEY TOPICS: slope of a line, point-slope form, slope-intercept form, general form of a line, distance of a point from a line, angle between two lines, parallel and perpendicular lines, collinearity of points, intersection of lines, family of lines
The equation of the line with slope 3 passing through (2, 1) is:
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Two lines y = m₁ x + c₁ and y = m₂ x + c₂ are perpendicular iff:
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The distance from origin to the line 3x + 4y − 5 = 0 is:
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The line passing through (0, 3) and (2, 0) has slope:
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Find the slope of the line joining the points (1, 3) and (4, 9).
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Write the equation of the line in slope-intercept form with slope −2 and y-intercept 5.
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Find the equation of the line passing through the points (1, 2) and (3, 8).
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Find the perpendicular distance from the origin to the line 3x + 4y = 12.
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Convert the equation y = 3x + 4 into general form.
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Find the equation of the line passing through the point of intersection of the lines x + y = 5 and 2x − y = 1, and parallel to the line 3x + 4y = 7.
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Show that the points (1, 2), (3, 6) and (5, 10) are collinear.
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Find the equation of the line passing through (3, 4) and perpendicular to 2x − 3y + 5 = 0.
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Find the angle between the lines y = 2x + 3 and y = 3x − 1.
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Find the area of the triangle formed by the lines y = 0, x = 4 and y = x + 2.
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Compare slope-intercept form and point-slope form of a straight line with the help of a table.
Assertion (A): Slope of a line through (x₁ y₁) and (x₂ y₂) is (y₂ − y₁)/(x₂ − x₁) for x₁ ≠ x₂.
Reason (R): Slope measures the rate of change of y with respect to x.
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Assertion (A): Two non-vertical lines are parallel iff their slopes are equal.
Reason (R): Parallel lines never meet so they share the same direction (slope).
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Assertion (A): Two non-vertical lines are perpendicular iff the product of their slopes is −1.
Reason (R): The negative reciprocal relation reflects that perpendicular lines meet at 90°.
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Assertion (A): The equation of the x-axis is y = 0.
Reason (R): Every point on the x-axis has y-coordinate equal to 0.
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Assertion (A): A line with x-intercept a and y-intercept b satisfies x/a + y/b = 1.
Reason (R): The line passes through (a 0) and (0 b) and the equation can be derived by the two-point form.
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Statement 1: The equation y = mx + c has slope m.
Statement 2: The equation y = mx + c has y-intercept c.
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Statement 1: A horizontal line has slope 0.
Statement 2: A vertical line has undefined slope.
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Statement 1: Two lines with slopes 2 and −1/2 are perpendicular.
Statement 2: Their slopes have product −1.
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Statement 1: The point-slope form of a line is y − y₁ = m(x − x₁).
Statement 2: The two-point form generalises the point-slope form using two known points.
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Statement 1: A line with x-intercept 4 and y-intercept 3 has equation x/4 + y/3 = 1.
Statement 2: An equation in intercept form passes through (a 0) and (0 b).
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The slope of the road equals:A3/4B4/3C1D−1
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The slope of the bridge (perpendicular) equals:A4/3B−3/4C3/4D−4/3
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Write the equation of the bridge in slope-intercept and general forms.
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The area of the triangle equals:A3B4C6D12
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The slope of side BC equals:A3/4B−3/4C4/3D−4/3
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Write the equation of side BC in intercept form.
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The distance from (3, −2) to the line equals:A5B5/√7C23/5D5/2
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The formula |Ax₀ + By₀ + C|/√(A² + B²) gives:APerpendicular distance from a point to a lineBDistance between two parallel linesCDistance between two intersecting linesDLength of the line
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Compute the distance step by step.
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Study the slopes of various lines:
| Line | Slope |
|---|---|
| y = 2x + 3 | 2 |
| x = 4 | undefined |
| y = −5 | 0 |
| y = (1/2)x − 1 | 1/2 |
| 3x + 4y = 12 | −3/4 |
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The slope of the line y = 2x + 3 equals:A2B1/2C−3/4DUndefined
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The slope of the line x = 4 is:ADefined non-zeroBDefined and zeroCUndefinedDNegative
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Find the slope of the line 5x − 2y + 7 = 0.
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Study the equations of standard lines:
| Form | Equation |
|---|---|
| Slope-intercept | y = mx + c |
| Point-slope | y − y₁ = m(x − x₁) |
| Two-point | (y − y₁)/(y₂ − y₁) = (x − x₁)/(x₂ − x₁) |
| Intercept | x/a + y/b = 1 |
| General | Ax + By + C = 0 |
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The form y − y₁ = m(x − x₁) is the:ASlope-interceptBPoint-slopeCTwo-pointDIntercept
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The form x/a + y/b = 1 is the:ATwo-pointBSlope-interceptCInterceptDGeneral
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Convert y − 2 = 3(x + 1) to general form.
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From the points in the table, find the slope of each line segment and identify which two are parallel and which are perpendicular.
| Line | Point 1 | Point 2 |
|---|---|---|
| L1 | (1, 2) | (4, 8) |
| L2 | (0, 3) | (3, 9) |
| L3 | (2, 5) | (4, 4) |
Study the line y = 2x + 3 with slope-intercept marked and answer:
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The slope of the line equals:A1B2C3D−2
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The y-intercept is at the point:A(0, 0)B(0, 2)C(0, 3)D(3, 0)
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State the slope-intercept form and identify m and c.
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